A man bought a number of turkeys at a cost of $60.00, and after reserving
fifteen of the birds he sold the remainder for $54.00, thus gaining 1O¢ a head
by these. How many turkeys did he buy?
goli202084 Answered question
Let's assume, man bought x turkeys for $60, thus price per turkey is 60 ____ x He kept 15 turkeys and sold the remainder for 54$ gaining 10 cents per turkey. Let's convert this into algebraic expressions Remaining number of turkeys = x - 15 Selling price of x-15 is 54$, so selling price per turkey is 54 ____, but he made 10 cents (0.1$) profit per turkey so x-15 54 60 ____ - ____ = 0.1 ---------(1) x-15 x 54x-60x+900 = 0.1*x*(x-15) 10*(-6x+900) = x*(x-15) -60x+9000 = x^2-15x x^2+45x-9000 = 0 => (x+120)(x-75) = 0 => x = -120 or x = 75 Discarding -ve value, the man bought 75 turkeys for 80 cents each and sold, 60 turkeys (reserving 15 for himself) for 90 cents each making total profit of 10 cents per turkey
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